Thursday Thought

Why is diversity important in an outside the classroom?

Wisdom Wednesdays

Teaching Tuesdays-Run on Sentences

Run-On Sentences

A run-on sentence occurs when two or more independent clauses (also known as complete sentences) are connected improperly.

Example: I love to write papers I would write one every day if I had the time.

There are two complete sentences in the above example:

Sentence 1: I love to write papers.

Sentence 2: I would write one every day if I had the time.

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One common type of run-on sentence is a comma splice. A comma splice occurs when two independent clauses are joined with just a comma.

Example of a comma splice: Participants could leave the study at any time, they needed to indicate their preference.

Sentence 1: Participants could leave the study at any time.

Sentence 2: They needed to indicate their preference.

Some comma splices occur when a writer attempts to use a transitional expression in the middle of a sentence.

Example of a comma splice: The results of the study were inconclusive, therefore more research needs to be done on the topic.

Sentence 1: The results of the study were inconclusive

Transitional expression (conjunctive adverb): therefore

Sentence 2: More research needs to be done on the topic

To fix this type of comma splice, use a semicolon before the transitional expression and add a comma after it. See more examples of this on the semicolon page.

Revision: The results of the study were inconclusive; therefore, more research needs to be done on the topichttp://academicguides.waldenu.edu/writingcenter/grammar/runonsentences.

Math Monday-Geometric Formula Review

Geometric Formula Review

Purplemath

There are many geometric formulas, and they relate height, width, length, or radius, etc, to perimeter, area, surface area, or volume, etc. Some of the formulas are rather complicated, and you hardly ever see them, let alone use them. But there are some basic formulas that you really should memorize, because it really is reasonable for your instructor to expect you to know them.

For instance, it is very easy to find the area A of a rectangle: it is just the length l times the width w:

Arect = lw

MathHelp.com

The "rect" in the formula above is a subscript, indicating that the area "A" being found is that of a rectangle. Because I'm going to be discussing area, volume, etc, formulas for different shapes, I'm using the subscripts to make clear the shape to which the particular formula refers (while using "A" for "area", "SA" for "surface area", "P" for "perimeter", and "V" for "volume"). Subscripting of this sort can be a useful technique for making your meaning clear, so try to keep this in the back of your mind for possible future use.

If you look at a picture of a rectangle, and remember that "perimeter" means "length around the outside", you'll see that a rectangle's perimeter P is the sum of the top and bottom lengths l and the left and right widths w:

Prect = 2l + 2w

Squares are even simpler, because their lengths and widths are identical. The area A and perimeter P of a square with side-length s are given by:

Asqr = s2

Psqr = 4s

You should know the formula for the area of a triangle; it's easy to memorize, and it tends to pop up unexpectedly in the middle of word problems. Given the measurements for the base b and the height h of the triangle, the area Aof the triangle is:

$A_{\text{tri}} = \dfrac{1}{2} bh$

Of course, the perimeter P of the triangle will just be the sum of the lengths of the triangle's three sides.

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You should know the formula for the circumference C and area A of a circle, given the radius r:

Acir = πr2

Ccir = 2πr

("π" is the number approximated by 3.14159 or the fraction 22/7)

Remember that the radius of a circle is the distance from the center to the outside of a circle. In other words, the radius is just halfway across. If they give you the length of the diameter, being the length of a line through the middle going all the way across the circle, then you'll first have to divide that value in half in order to apply the above formulas.

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The above are all "flat", two-dimensional shapes. Sometimes you will have to deal with three-dimensional shapes, such as cubes or cones. For these kinds of shapes, you'll be finding the surface area (if you were painting the object, this is the area that you'd have to cover) and the volume (being the interior space that you could fill, were the shape hollow).

The formula for the volume V of a cube is easy, since the length, the width, and the height are all the same value s:

Vcube = s3

The formula for the surface area (the area you would measure if you needed to paint the ouside of the cube) is fairly easy, too, since all the sides have the same square area of s2. There are six sides (top, bottom, left, right, front, and back), so the surface area SA is:

SAcube= 6s2

The formulas get a bit more complicated for a "rectangular prism", which is the technical term for a brick. The volume V is still fairly simple, being length times width times height:

Vrect = lwh

The surface area formula is a bit more ornate. (Try to follow the reasoning that I'm going to use, because you'll probably forget the formula, but it's easy to recreate if you just take a little time and think about it.) The top and bottom of the "brick" have the same area, being length times width. The left and right sides of the brick have the same area, being width times height. And the front and back of the brick have the same area, being length times height. (Draw a picture, labelling the dimensions, if you're not sure of this.) Then the formula for the surface area SA of a brick is:

SArect= 2lw + 2wh + 2lh

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Cylinders (which are like tubes, but with caps on the ends) also come up occasionally. The volume V of a cylinder is easy: it's the area of the end (which is just the area of the circle) times the height h:

Vcyl = πr2h

The surface area SA is the area of the ends (which are just circles), plus the area of the side, which is a circle's circumference times the height h of the cylinder:

SAcyl = 2πr2 + 2πrh

Depending on the class you're taking, you might also need to know the formula for the volume V of a cone with base radius r and height h:

$V_{\text{cone}} = \dfrac{1}{3} \pi r^2$

...or the volume V of a sphere (a ball) with radius r:

$V_{\text{sph}} = \dfrac{4}{3} \pi r^3$

You may notice other formulas cropping up in your homework or classroom exercises. You may need to memorize these other formulas (there are many!), so be sure to check with your instructor before the test to learn which you will be expected to know.

Financial Friday

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Thursday Throught

"Life can only be understood backward, but it must be lived forward"-Soren Kierkegaard

What do you think this quote means? How can you apply the quote's message to your daily life?

Words of Wisdom

"The more you use, the more brain you will have to use"-George A. Dorsey